His average is 86 so it is below 90. to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.
On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order
The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order
Lamont needs to get a 99 on his next test to have an average of exactly 90.
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Answer:
Loss of $1.20
Step-by-step explanation:
The possible outcomes for this lottery and their probabilities are:
- a 1 in 100 chance of winning $450
- a 2 in 100 chance of winning $120
- a 4 in 100 chance of winning $30
- a 93 in 100 chance of losing $10
Therefore, the expected value of this lottery when buying one ticket is:

Therefore, you are expected to lose $1.2 per ticket.
R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32
Answer:
The last table given See attached image)
Step-by-step explanation:
Notice that they are asking for the inverse function to the one with the detailed relationship given. The original relationship was assigning to the Domain of number of people attending, the Range of values for charges.
Therefore, the inverse function will be assigning in the opposite way: from the average charges (now the Domain of this relationship), to the number of people attending (now the Range of this relationship). The relationship should also maintain the original element to element connection:
What was:
(20, $10) should now be ($10, 20)
(26, $6.25) should now be ($6.25, 26)
(35, $4) should now be ($4, 35)
This is exactly represented by the last table (see also image attached)
I think it is 1/2
hope this helped