Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
The houses form a right triangle. Using a²+b²=c² you will find that the distance from Clayton’s house to Danny’s would be 4.1 miles. Adding it all up, the distance would be 9.1 miles of walking.
Answer:
4.24 km
Step-by-step explanation:
The x-component of the displacement after the turn is ...
d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km
Adding this to the displacement before the turn, we have ...
x-component of displacement = 2.83 km + 1.41 km = 4.24 km
If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days
One number is 18 and the other is 22
