X/29 = 2/5.8
(X) x (5.8). (2) x (29)
5.8x = 58
58/5.8
X = 10
Alright, so what we can take as a given is that arcDE/2= ∠CDE=2x+20 since the arc corresponding to the angle is 2*the angle. To solve for arcDE, we multiply both sides by 2 to get 2(2x+20)=4x+40=arcDE. Since the arcs in a circle add up to 360 degrees and we only have -20+30x and arcDE, we have -20+40+4x+30x=360 using the associative property. Simplifying, we get 20+34x=340. Subtracting 20 from both sides, we get 340=34x. Next, we can divide both sides by 34 to get 10=x.
The sum (for all polygons) of the exterior angles are 360. So, 360/11 is 32.72
hope this helps!
Sqr root of 56 - sqr root of 14 + sqr root of 126= sqr root of (4x14) - sqr root of 14 + sqr root of (9x14)= 2(sqr root of 14) - (sqr root of 14) + 3(sqr root of 14)= 4(sqr root of 14)
The right answer will be B.
Answer:
54
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