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iVinArrow [24]
3 years ago
9

Which statement is true? Question 7 options: A) |–3| = 3 and –|–4| = –4 B) |–3| = 3 and –|4| = 4 C) –|3| = 3 and |4| = 4 D) |–3|

= 3 and |–4| = –4​
Mathematics
1 answer:
algol133 years ago
4 0

Answer:A

Step-by-step explanation:

The absolute value of -3 is 3. The absolute value of -4 is 4, but since there is a second negative, it makes the positive 4 and negative again.

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What is the approximate area of the circle shown below 9.4 cm
aivan3 [116]

Answer:

Step-by-step explanation:

A= πr²

A= 22/7 multiply by the radius.

Divide 9.4cm by 2.

Whatever you get is your answer. Now take the formula I have shown you above. Whatever you get is your answer.

6 0
3 years ago
You unfold chicken wire to make a circular pen. The area of the pen is 78.5 square meters. How many meters of chicken wire do yo
Lelu [443]
Circular pen means you are going to use Area = Pi(r^2). 

So 78.5 = pi(r^2). Divide by pi on both sides to get r^2 = 78.5/pi. Take the square root of that to get r or radius = approximately 4.99. If you need an exact answer then use \sqrt{ \frac{78.5}{ \pi } } for the next part because you are not done yet.

Plug whatever R you use into the circumference formula of Circumference = 2(pi)(r).

If you use 4.99, you do 2(pi)(4.99) which is approximately 31.35. If you use the exact answer, you do 2(pi)(\sqrt{ \frac{78.5}{ \pi} }) which gives you approximately 31.41. 

Either way you'll need about 31 meters of chicken wire but the 31.40796 or ~31.41 is closer to the exact answer. 
8 0
3 years ago
Gina wants to ship 3 books that weigh 2 7/16 pounds, 1 7/8 pounds and 1/2 pound. the maximum weight she can ship is 6 pounds. ho
pshichka [43]
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6 0
3 years ago
Read 2 more answers
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

6 0
3 years ago
How would the number 6,870,000,000,000,000 appear in scientific notation on a calculator screen
kvv77 [185]
687 to the 15 power I believe
5 0
3 years ago
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