Which polygon appears to be regular?

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

2 years ago

Select all that apply. Which of the following are proportions? 25/10=5/2,3/4=8/10,2/8=3/12,3/4=15/20

8_murik_8 [283]

Answer:

$\frac{25}{10} = \frac{5}{2}$ is in proportion.

$\frac{3}{4} = \frac{8}{10}$ is not in proportion.

$\frac{2}{8} = \frac{3}{12}$ is in proportion.

$\frac{3}{4} = \frac{15}{20}$ is in proportion.

Step-by-step explanation:

The first example is $\frac{25}{10} = \frac{5}{2}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{5}{2}$ ) from the fraction $\frac{25}{10}$ by dividing its numerator and denominator by 5.

The second example is $\frac{3}{4} = \frac{8}{10}$ and it is not in proportion.

This is because, you can not get the simplest fraction ( $\frac{3}{4}$ ) from the fraction $\frac{8}{10}$ after simplification.

The third example is $\frac{2}{8} = \frac{3}{12}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{1}{4}$ ) from the fraction $\frac{2}{8}$ by dividing its numerator and denominator by 2 and from the fraction $\frac{3}{12}$ by dividing its numerator and denominator by 3.

The fourth example is $\frac{3}{4} = \frac{15}{20}$ and it is in proportion.

This is because, you will get the same simplest fraction ( $\frac{3}{4}$ ) from the fraction $\frac{15}{20}$ by dividing its numerator and denominator by 5. (Answer)

3 0

2 years ago

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A door measuring 72cm by 1.8m was manufactured by a carpenter who prepared it using 74cm by 1.82m. Find the percentage error in

pantera1 [17]

Step-by-step explanation:

so a door is a rectangle and they want the answer in breadth 72 cm and 74cm into m

then divie it by by

8 0

2 years ago

Given the first type of plot indicated in each pair, which of the second plots could not always be generated from it?

Kisachek [45]

Answer:

d. box plot, stem and leaf

Step-by-step explanation:

The box plot depicts the five number summary minimum, 1st quartile, median, third quartile and maximum while stem and leaf plot shows every observation in data. So, when the box plot is given, we can't generate stem and leaf plot for the data because we don't have sufficient information in this scenario i.e., we don't have every data value to generate stem and leaf plot. Whereas, If the stem and leaf plot is given first then we can generate box plot from it because we have every data value to compute 5-number summary to generate box plot.

a. From dot plot, the histogram can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate histogram.

b. From dot plot, the stem and leaf plot can be generated because dot plot represents every data value in the form of dots and from every data value, we can generate stem and leaf plot.

c. From stem and leaf plot, the dot plot can be generated because stem plot represents every data value in the form of stem and leaf i.e. 12 can be represented as 1 for a stem and 2 for a leaf (1 2) and so, from every data value we can generate dot plot.

d. From box plot, the stem and leaf plot can't be generated and the reason is explained in first paragraph. So, when the first type of plot is box plot then from it second plot stem and leaf plot can't be generated.

6 0

3 years ago

Consider the equation 4x=8.<br> Which value could be substituted x to make the equation TRUE?

const2013 [10]

X=2 (4 x 2 = 8) so 2 is the answer

6 0

3 years ago

Read 2 more answers