Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.
The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818
From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%
Answer: 57.2%
x = All real numbers or 0.
First you should distribute both sides of the equation. This gives you 42x+42=42x+42.
Then, subtract 42 from both sides. This gives you 42x=42x.
Now, divide 42 on both sides. This gives you x=0 or all real numbers.
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.



b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
98 divided by 2 equals 49
55 divided by 5 equals 11