No he's not correct
<span>(3 – 6y2)(y2 + 2)
= 3(y2) -6(y2)(y2) - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
= -6y4 - 9y2 +6</span>
<span>The first step you need to do is to rewrite
x+y=3
as y=3-x
</span><span>Now we can replace the y in the equation with our newfound value for y, which is
y=3-x.
So lets write it now like this
Q=x^2+2(3-y)^2
=x^2+18-12x+2x^2
=3x^2+18-12x
</span>Hope this helps
Hi!
C. v + 15
Barry read for 15 MORE minutes than Robert.
Answer:
<h2>
x = −7 and x = 33</h2>
Step-by-step explanation:

Answer:
<h3>105m²</h3>
Step-by-step explanation:
AREA=


=105m²