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jarptica [38.1K]
3 years ago
10

B(h+w)=4h(11-j), solve for w

Mathematics
1 answer:
frozen [14]3 years ago
4 0

Answer:

W=4h(11-j)/b-h

Step-by-step explanation:

Eliminate variables on the left side first.

b(h+w) = 4h (11-j) - so, divide b by both sides

(h+w)/b=4h(11-j)/b  then, eliminate h by subtracting on both sides.

(h+w)-h=4h(11-j)/b - h   (h is eliminated on the left side and now you are left with

W=4h(11-j)/b - h

   

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100 POINTS AND BRAINLIEST! FULLY CORRECT AND EXPLANITORY ANSWERS ONLY!
Fed [463]

Answer:

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

5 0
2 years ago
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Complete the proof....
abruzzese [7]

Answer:

The correct options are;

1. Definition of supplementary angles

2. m∠1 + m∠2 = m∠1 + m∠3

3. m∠2 = m∠3

4. Definition of Congruent Angles

Step-by-step explanation:

The two column proof is presented as follows;

Statement           {}                                  Reason

1. ∠1 and ∠2 are supplementary    {}     Given

 {} ∠1 and ∠3 are supplementary

2. m∠1 + m∠2 = 180°        {}                    Definition of supplementary angles

{}   m∠1 + m∠3 = 180°

3. m∠1 + m∠2 = m∠1 + m∠3      {}          Transitive Property

4. m∠2 = m∠3       {}                               Subtraction Property of Equality

5. ∠2 ≅ ∠3       {}                                    Definition of Congruent Angles

Given that angles ∠1 and ∠2 are supplementary angles and angles ∠1 and ∠3 are are also supplementary angles, then the sums of m∠1 + m∠2 and m∠1 + m∠3 are equal, therefore, ∠2 and ∠3 have equal quantitative value and therefore ∠2 = ∠3 and by definition, ∠2 ≅ ∠3.

3 0
2 years ago
Solve 7x 6 < 3(x - 2).{x | x > -3}{x | x < -3}{x | x < -2}{x | x < 0}
Lelechka [254]
7x + 6 < 3(x - 2)
7x + 6 < 3x - 6
7x - 3x < -6 - 6
4x < -12
x < -12/4
x < -3

<span>{x | x < -3}</span>

6 0
3 years ago
An open box is to be made out of a 6-inch by 14-inch piece of cardboard by cutting out squares of equal size from the four corne
lawyer [7]

Answer:

The dimensions of the resulting box that has the largest volume is 1.3 inches x 1.3 inches

Step-by-step explanation:

Card board size is L= 14 inches and

W = 6 inches

Let x be the size of equal squares cut from 4 corners and bent into a box whose size is now;

L = 14 − 2x , W = 6 −2x and h = x inches.

Volume of the box is given as;

V = (14 −2x)(6−2x)x

V =(4x² − 40x + 84)x

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Now, for the maximum value,

dV/dx =0

Thus,

dv/dx = 12x² - 80x + 84 = 0

Using quadratic formula

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x = (80 + 48.66)/24 or (80-48.66)/24

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Thus, x = 1.31 inches

Let us use the Second Derivative Test to verify that V has a local maximum at x = 1.31.

Thus;

d²v/dx² = 24x - 80 = 24(1.31) - 80 = -48.56

This is less than 0 and therefore, the volume of the box is maximized when a 1.31 inch by 1.3 inch square is cut from the corners of the cardboard sheet.

3 0
3 years ago
A dealer selects a card at random from a standard deck of 52 cards.
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Answer:

a) you are correct about a.

b)2/13 chance

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