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Andreyy89
3 years ago
13

Mrs. Deery has 6 large pieces of construction paper for an art project. She has 24 students in her class. What fraction of the p

aper will each student receive if it is divided into equal parts?
Mathematics
2 answers:
svp [43]3 years ago
8 0

Answer:

Step-by-step explanation:

Dahasolnce [82]3 years ago
5 0
Since 24/6 = 4, cut each construction paper into four slices, so you have 24 total. Hope this helps!

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I'm so confused!! What would they be and why??
Natalka [10]
I dont understand the question
5 0
3 years ago
According to the diagram which of the following statement is true?
d1i1m1o1n [39]

We know that :

✿  \mathsf{Cos\theta = \frac{Adjacent\;Side}{Hypotenuse}}

✿  \mathsf{Sin\theta = \frac{Opposite\;Side}{Hypotenuse}}

✿  \mathsf{Tan\theta = \frac{Opposite\;Side}{Adjacent\;Side}}

From the Figure :

✿  \mathsf{Cosx = \frac{4}{5}}

✿  \mathsf{Sinx = \frac{3}{5}}

✿  \mathsf{Tanx = \frac{3}{4}}

Only 1st Statement is True

1st Option is the Answer

4 0
3 years ago
A race is 7/10 kilometers long. Maya ran 9 of these races. How far did she run altogether? Write your answer in simplest form.
gayaneshka [121]

Answer:

She ran

6 \frac{3}{10} km \: or \: 6.3 \: km

Step-by-step explanation:

To find the answer you multiply the amount of races (9) by the length of each race (7/10 km).

\frac{7}{10}  \times  \frac{9}{1}  =  \frac{63}{10}  \: or \: 6 \frac{3}{10}

8 0
1 year ago
9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
2 years ago
Three runners recorded their times for the 40-yard dash
egoroff_w [7]

Answer:

The fastest runner is Alana because she had the least mean running time. The most consistent runner is Lorena because she had the least interquartile range value.

6 0
3 years ago
Read 2 more answers
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