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Novay_Z [31]
2 years ago
10

The perimeter of the rectangle below is 68 cm. The perimeter of the triangle is 60 cm. Find the length of the hypotenuse of the

triangle​
Mathematics
1 answer:
Inessa05 [86]2 years ago
6 0

The right triangle is assumed to be inscribed in the rectangle, such that

hypotenuse is the diagonal of the rectangle.

  • The length of the hypotenuse of the triangle is <u>26 cm</u>.

Reasons:

Let <em>x</em> and<em> </em><em>y</em> represent the length of the sides of the rectangle

Whereby the base and height of the right triangle are the same as the

length and width of the rectangle, we have;

Perimeter of the rectangle = 2·x + 2·y = 68

Therefore;

\displaystyle x + y = \frac{68}{2} = 34

x + y = 34

The base of the right triangle = x

The height of the right triangle = y

By Pythagoras's theorem, the length of the hypotenuse side = √(x² + y²)

Therefore; Perimeter of the right triangle = x + y + √(x² + y²) = 60

Which gives;

∴√(x² + y²) = 60 - (x + y) = 60 - 34 = 26

The length of the hypotenuse side, √(x² + y²) = <u>26 cm</u>

Learn more about Pythagoras's theorem here:

brainly.com/question/8171420

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A boy's age is three times the age of his sister. Their ages together total 16 years.
jok3333 [9.3K]

Answer:

Sister's age: 4

Brother's age: 12

8 0
2 years ago
If a b and m∠2 = 71°, what is m∠1?
Nikolay [14]

Answer:

  71°

Step-by-step explanation:

In order to be able to solve this problem, we must assume the relation between lines "a" and "b" is that they are parallel.

If a║b, then ∠1 and ∠2 are corresponding, hence congruent.

  m∠1 = m∠2 = 71°

8 0
3 years ago
Find the area of ABC with vertices A(3,-6), B(5,-6), and C(7,–9).
stellarik [79]

Area of a triangle ABC with the given vertices is 3 square units.

Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).

<h3>What is the area of triangle formula in coordinate geometry?</h3>

In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.

Area of a triangle = \frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)

Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)

Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)

= 1/2 (|3(3)+5(-3)+7(0)|)

= 1/2 (|(9-15)|)

= 1/2 × 6

= 3 square units

Therefore, area of a triangle ABC with the given vertices is 3 square units.

To learn more about the area of a area of triangle with vertices visit:

brainly.com/question/26633662.

#SPJ1

7 0
1 year ago
What is the result when 8x^3+6x^2+15x+7 divides by 2x + 1
sveticcg [70]

Answer:

Step-by-step explanation:

3 0
3 years ago
Which expression can be used to find the surface area of the following triangular prism? *picture of a triangular prism* Choose
KIM [24]

Answer:

A. 24+24+120+160+200

Step-by-step explanation:

Surface area of the triangular prism= addition of the area of each shape that forms the prism

There are two triangles

Area of a triangle=1/2*base*height

=1/2*8*6

=1/2*48

=24

Area of two triangles=24+24

There are 3 rectangles with different dimensions

Back rectangle=length×width

=20×6

=120

Bottom rectangle=length ×width

=20x8

=160

Top rectangle=length × width

=20×10

=200

Surface area =Area of two triangles + Back rectangle + Bottom rectangle + Top rectangle

=24+24+120+160+200

5 0
2 years ago
Read 2 more answers
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