The initial deceleration is 4 m/s^2, so this means that considering the first line segment,
.
The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so
.

Remember for any two polygons
Area of polygons is directly proportional to square of sides
So
- BC²/XY²=135/15
- 15²/XY²=9
- (15/3)²=XY²
- XY=5in
#35
- HJ²/XY²=168/378
- 8²/XY²=0.44
- XY²=64/0.44
- XY²=145.45
- XY\approx 12+
Let y = 12 e^2x
e^2x = y/12
Taking
[email protected]ln e^2x = ln (y/12)
2x = ln (y/12)
x = (1/2) ln (y / 12)
so the inverse h-1(x) = (1/2) ln ( x / 12)
Maybe...... E if that’s not right then try..... b