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Anestetic [448]
2 years ago
9

PLEASE HELP making Brainliest if correct

Mathematics
1 answer:
Oksana_A [137]2 years ago
6 0
Can’t see the whole question, but they are congruent by ASA (if that is what they asked)
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Least common denumertor of 11/3 9/10
Alisiya [41]
30 since that’s the lowest number both 3 and 10 can fit in
8 0
2 years ago
First question. The midpoint of SR is...
Blizzard [7]

The formula of a midpoint SR:

M\left(\dfrac{x_S+x_R}{2},\ \dfrac{y_S+y_R}{2}\right)

We have

S(4, 1) and M(7, -5)

Substitute:

\dfrac{4+x_R}{2}=7\qquad|\cdot2\\\\4+x_R=14\qquad|-4\\\\x_R=10\\\\\dfrac{1+y_R}{2}=-5\qquad|\cdot2\\\\1+y_R=-10\qquad|-1\\\\y_R=-11

<h3>Answer: R(10, -11)</h3>
6 0
3 years ago
Hello
Dafna11 [192]

Answer:

X=5

Exlanation

8 0
3 years ago
100% pure gold is 24 karat gold, which is too soft to be made into jewelry most call Jory is 14 karat gold proximally 58% gold 1
denis-greek [22]

Answer:

The amount of gold used in a 200 g 14 gold bracelet is 116 g.

Step-by-step explanation:

Since a 14 karat jewell is stated to have aproximally 58 % of it's weigh in gold we need to take the total weigh of the jewel in question and find that percentage of it's weigh. In order to find that percentage we'll first convert that number into a decimal, we do that by dividing it by 100, so we have 58% = 58/100 = 0.58 we can multiply this value by the weigh of the jewel to find the amount of gold used. So we have:

gold used = total weigh*0.58 = 200*0.58 = 116 g

5 0
3 years ago
How would you differentiate this problem?
DochEvi [55]

Answer:

hope this helps you in some way

7 0
3 years ago
Read 2 more answers
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