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mariarad [96]
3 years ago
5

The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f

eet, what are it’s dimensions?
Mathematics
1 answer:
Temka [501]3 years ago
8 0
Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct
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