The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f eet, what are it’s dimensions?
1 answer:
Let's first say that L=W+44 and then remember that perimeter is P=2L+2W replace the L with W+44 we then get P=2(W+44)+2W, now I'll solve it P=2W+88+2W P=4W+88 substitute 288 for P 288=4W+88 200=4W 50=W so now we now how wide the court is. add 44 to find the length which gives you L=94 as always plug the numbers back into your perimeter equation to ensure L and W are correct
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Answer:
im pretty sure its ACD
Step-by-step explanation:
The pattern is: ( a - b )² = a² - 2 a b + b² ( square of last term of binomial - the missing term) x² - 2 · 8 · x + 8² = x² - 16 x + 64 = ( x - 8 )² The missing term is: 64
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y=$350 because that is her total.
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B=$200 because that's how much the console cost.
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Answer:
54.8275862069
Step-by-step explanation:
If you want rounded than 54