$\frac{4 \sqrt{400} }{4 \sqrt{5} } = \frac{ \sqrt{400} }{ \sqrt{5} } = \\ \frac{20}{ \sqrt{5} } * \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{20 \sqrt{5} }{5} } = 4 \sqrt{5}$
Thank you.

7 0

3 years ago

Read 2 more answers

Simplify: (−12az2−2z3)+(−2a3+7a2z)−(−4a2z+8az2)

Setler [38]

Answer:

$\large{ \boxed{ \tt{ - 20a {z}^{2} - 2 {z}^{3} - 2 {a}^{3} + 11 {a}^{2} z }}}$

- Please see the attached picture for full solution!:)

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3 0

2 years ago

Solve the following system.

Stolb23 [73]

From the second equation y=-1-x so we can write -2x²+3x-1=-1-x.
So -2x²+4x=0, 2x(-x+2)=0, therefore x=0 or 2 and the corresponding y values are -1 and -3.
We can write the answers as ordered pairs (0,-1) and (2,-3).

4 0

3 years ago