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finlep [7]
3 years ago
10

Write a function that represents the situation. Your $840 annual bonus increases by 5% each year

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

f(x)  = (840)\times (1.05)^{x} where f(x) is the bonus every year and x is in number of years

Step-by-step explanation:

The function that represents the situation where $840 annual bonus increases by 5% each year is given by

f(x)  = (840)\times (1.05)^{x} where f(x) is the bonus every year and x is in number of years

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Answer:

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Step-by-step explanation:

Triangles have same angles. This means that they are proportion.

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when you cross multiply to solve x, 50x = 1080

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lutik1710 [3]
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3 years ago
Angela had $22.70 to spend on groceries. After buying 8 pineapples, she had $3.50 left. If each pineapple was the same price, wh
sesenic [268]

Answer:

$2.40

Step-by-step explanation:

First, you would do 22.70 minus 3.50, to get 19.20.

Then, you would divide 19.20 by 8, to get 2.4.

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3 0
2 years ago
A. f(x) = l-2xl - 3<br> Domain: {1, 2, 3}<br> Find the range
gizmo_the_mogwai [7]

Hello there!

We are given the function:

\displaystyle \large{ f(x) =  | - 2x|  - 3} \\

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

<u>x</u><u> </u><u>=</u><u> </u><u>1</u>

\displaystyle \large{ f(1) =  | - 2(1)|  - 3} \\   \displaystyle \large{ f(1) =  | - 2|  - 3} \\

Recall that any numbers in absolute value are always positive.

\displaystyle \large{ f(1) =  2 - 3} \\   \displaystyle \large{ f(1) =   - 1} \\

<u>x</u><u> </u><u>=</u><u> </u><u>2</u>

\displaystyle \large{ f(2) =  | - 2(2)|  - 3} \\   \displaystyle \large{ f(2) =  | - 4 |   - 3} \\   \displaystyle \large{ f(2) =  4 - 3} \\   \displaystyle \large{ f(2) =  1}

<u>x</u><u> </u><u>=</u><u> </u><u>3</u>

\displaystyle \large{ f(3) =  | - 2(3)|  - 3} \\   \displaystyle \large{ f(3) =  | - 6|   - 3} \\   \displaystyle \large{ f(3) =  6 - 3} \\   \displaystyle \large{ f(3) =  3}

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0
3 years ago
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ycow [4]

Answer:

Step-by-step explanation:

5 0
2 years ago
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