I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept. 2x + 3y = 12 3y = -2x + 12 y = -2/3x + 4......slope is -2/3 and y int is (0,4)
x int can be found by subbing in 0 for y and solving for x 2x + 3y = 12 2x + 3(0) = 12 2x = 12 x = 6.....so x int is (6,0)
start at y int (0,4).....and since the slope is -2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces....keep doing that and u should cross the x axis at (6,0)
