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3 years ago

Anyone know this ? I don’t understand math

Mathematics

2 answers:

ch4aika [34]3 years ago

8 0

The answer is 99cm^2.

MrMuchimi3 years ago

5 0

Answer:

99cm^2

Step-by-step explanation:

When finding an area of a triangle, you multiply base times height and then divide by 2.

In this case,

Height:11

Base: 18

So then apply the formula:

$\frac{11*18}{2}$

Solve (using a calculator lol)

We get 99

Don't forget units!

So the final answer is 99cm^2

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Round 9.17302 to the nearest thousandths tenths and nearest unit

statuscvo [17]

Answer:

170000

Step-by-step explanation:

17000

4 0

3 years ago

The proportion of traffic fatalities resulting from drivers with high alcohol blood levels in 1982 was approximately normally di

SSSSS [86.1K]

Answer:

a) The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.

b) The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.

In this problem, we have that:

Mean 0.569 and standard deviation 0.068. So $\mu = 0.569, \sigma = 0.068$

a. What proportion of states would you expect to have more than 65% of their traffic fatali- ties from drunk driving?

This is the value of X when Z has a pvalue of 0.65.

Z has a pvalue of 0.65 between $Z = 0.38$ and $Z = 0.39$ . So, we use $Z = 0.385$

$Z = \frac{X - \mu}{\sigma}$

$0.385 = \frac{X - 0.569}{0.068}$

$X - 0.569 = 0.068*0.385$

$X = 0.59518$

The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.

b. What proportion of deaths due to drunk driving would you expect to be at the 25th percentile of this distribution?

This is the value of X when Z has a pvalue of 0.25.

Z has a pvalue of 0.65 between $Z = -0.67$ and $Z = -0.68$ . So, we use $Z = -0.675$

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 0.569}{0.068}$

$X - 0.569 = 0.068*(-0.675)$

$X = 0.5231$

The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.

3 0

3 years ago

What is the radical expression that is equivalent 275

Katena32 [7]

Answer:

I have written 275 in 5 different ways I hope it helps plz Mark me brainliest

8 0

3 years ago

Mary is 9 years younger than anne. tom is twice older than anne. the sum of their ages is 95. how old is mary, tom and anne

horrorfan [7]

Mary is 17, Anne is 26, Tom is 52

7 0

3 years ago

Read 2 more answers

Use lagrange multipliers to find the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5).

horsena [70]

Lagrangian:

$L(x,y,z,\lambda)=x^2+(y-2)^2+(z-5)^2+\lambda(x-2y+3z-6)$

where the function we want to minimize is actually $\sqrt{x^2+(y-2)^2+(z-5)^2}$ , but it's easy to see that $\sqrt{f(\mathbf x)}$ and $f(\mathbf x)$ have critical points at the same vector $\mathbf x$ .

Derivatives of the Lagrangian set equal to zero:

$L_x=2x+\lambda=0\implies x=-\dfrac\lambda2$
$L_y=2(y-2)-2\lambda=0\implies y=2+\lambda$
$L_z=2(z-5)+3\lambda=0\implies z=5-\dfrac{3\lambda}2$
$L_\lambda=x-2y+3z-6=0$

Substituting the first three equations into the fourth gives

$-\dfrac\lambda2-2(2+\lambda)+3\left(5-\dfrac{3\lambda}2\right)=6$
$11-7\lambda=6\implies \lambda=\dfrac57$

Solving for $x,y,z$ , we get a single critical point at $\left(-\dfrac5{14},\dfrac{19}7,\dfrac{55}{14}\right)$ , which in turn gives the least distance between the plane and (0, 2, 5) of $\dfrac5{\sqrt{14}}$ .

7 0

3 years ago