Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)
The area of a trapezoid is (a+b)/2 * h
a is the length of the small base which is the one on the top and is 4cm
b is the length of the big base which is the one at the bottom and is 4 + 3 + 3 = 10cm
h is the height which is 7cm
So the area is (4+10)/2 * 7
A= 14/2 * 7
A= 7 * 7
A= 49 cm^2
Answer:
It can't be C or D. I think it could be A.
Answer:
4
Step-by-step explanation:
