The answer is a total of 9 hours
Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = 
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= 
= 
= 0.6
I can’t seen the question so it is hard to answer

which means there is some integer

for which

.
Because

and

, there are integers

such that

and

, and

We have

, which means there are four possible choices of

:
1, 42
2, 21
3, 14
6, 7
which is to say there are also four corresponding choices for

:
9, 378
18, 189
27, 126
54, 63
whose sums are:
387
207
153
117
So the least possible value of

is 117.
Answer:
if i'm right ted is 14 and ed is 21
Step-by-step explanation:
if ed is 7 years older than ted and is 3/2 times eds age, than we have to find out how much dose 2 represent in the equation 3/2 so we know that ed is seven years older than ted. so that means that if the equation 3/2 was 1/2, 1 would represent 7 years. (i hope your following me) so if 1 represents 7 than 2 must represent 14 and that would be the age of ted because in the equation 3/2 the 2 would represent teds age. and if the 2 represents teds age than 3 would be eds age. so 7 x 3 = 21. (this is my first time answering a question so sorry if i'm confusing)