All categories

2 years ago

If you used 4/7 of an item on Wednesday and 1/4 on Thursday, how much would you have left from the whole amount on Friday?

Mathematics

2 answers:

Alinara [238K]2 years ago

7 0

Answer: 5/28 left over.

Step-by-step explanation:

Make both of the fractions have the same denominator:

4/7 x 4/4 = 16/28

1/4 x 7/7 = 7/28

Combine:

16/28 + 7/28 = 23/28

So on Friday you have 5/28 of the item left over.

cupoosta [38]2 years ago

4 0

Answer:

5/28

Step-by-step explanation:

So first find a common denominator

4/7 + 1/4 can be translated as 16/28+7/28

16/28+7/28=23/28

NOw we have to subtract 23/28 from1, or 28/28, and that is 5/28

You might be interested in

Before you can make a pie chart you need to figure out how much of the circle belongs to each category. Suppose that you earned

svetoff [14.1K]

Answer:

missions-24

recreation-108

savings-144

school supplies-48

tithe-36

Step-by-step explanation:

so first convert all the given costs to cents by multiplying each amount with 100 then add all of them to get the total as 600

in a pie chart we know that it's a circle and all angles within the circle must add up to 360 so to get an angle for a certain cost that will represent it in the chart you have to take that cost over the total to get the fraction of the circle it will occupy multiplied by 360 to get it in degrees or which portion of 360 will it occupy hence

60/600×360=36

4 0

3 years ago

I don’t understand this and it’s due tomorrow. Pls help

olya-2409 [2.1K]

Answer: H

Step-by-step explanation:

So this is called a problem you would use PEMDAS or (please-excuse-my-dear-aunt-sally)

Parenthesis

Exponents

Multiply

Divide

Addition

Subtract

In this sens, since parenthesis are present you do them first so it would be H

3 0

2 years ago

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

2 years ago

What is the greatest common factor of 32 and 56

alina1380 [7]

Answer:

Step-by-step explanation:

List the factors of each number

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

Separate and find the GCF

Then the greatest common factor is 8.

Thanks for letting me help!!

4 0

2 years ago

Read 2 more answers

Plsss help me I don’t understand!!

inna [77]

Answer:

Step-by-step explanation:

in the "score" section all you do is add all them up. And because there is a negative for ALL the numbers, all you do is add a negative after you add all the SCORES

6 0

3 years ago