Answer:
Explanation:
brooke speed, u = 9 km/h = 2.5 m/s
Jamail speed, v = 4 km/h = 1.11 m/s
Let Booke is at (0, 0) and Jamail is at 35 m. So, at time t, the position of Brooke is (2.5 t , 0 ) and Jamail is (- 1.11 t, 35)
Let l be the distance between them.
Distance at t = 5 s
L = 39.38 m
Differentiate with respect to time
Put t = 5 s
dL/dt = 0.127 m/s
Answer:
Since Alice has a greater density it will also have a greater mass
Density = mass / volume
The potential energy at the surface of Alice will be greater and a higher kinetic energy will be required to escape the planet's gravitational pull.
PE = K M / R potential at surface is greater because mass is greater
KE = 1/2 M v^2 greater velocity required to overcome PE
Can you give the answer choices.??
Perpendicular. If a current carrying wire is placed in a magnetic field perpendicular to the wire it experiences a maximum force
Answer:
The ball was in air for 3.896 s
Explanation:
given,
g = 9.8 m/s², acceleration due to gravity,
If the launch angle is 45°, the horizontal range will be maximum.
The horizontal and vertical launch velocities are equal, and each is equal to
v_h = v cos θ
v_h = 27 × cos 45°
= 19.09 m/s.
The time to attain maximum height is one half of the time of flight.
v = u + at ∵ v = 0 (max. height)
19.09 - 9.8 t₁ = 0
t₁ = 1.948 s
The time of flight is twice of the maximum height time
2 t₁ = 3.896 s
The horizontal distance traveled is
D = v × t
D = 3.896×19.09
= 74.375 m
The ball was in air for 3.896 s