Question

A mosquito flaps its wings 600 vibrations per second which produces the annoying 600Hz buzz. The speed of sound is 340 m/s. How far does the sound travel between wing beats?

Answer 1

Answer:

$\lambda=0.57m$

Explanation:

The distance traveled by the sound wave between the beats of the wing is its wavelength, since it is defined as the distance traveled by a periodic disturbance that propagates in a cycle, is defined as:

$\lambda=\frac{v}{f}$

Where v is the speed of sound and f the frequency of the wing beats

$\lambda=\frac{340\frac{m}{s}}{600Hz}\\\lambda=0.57m$