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3 years ago

14

I need help on the third question

2 answers:

MakcuM [25]3 years ago

8 0

J+s is no more than 120
j+s≤120

if jacket is 20 more than 3 times skirt
j=20+3s

find max price for each

so we have
j+s≤120 and
j=20+3s

sub 20+3s for j

20+3s+s≤120
20+4s≤120
minus 20 oth sides
4s≤100
divide both sides by 4
s≤25

sub back

if s is 25
j=20+3s
j=20+3(25)
j=20+75
j=95

at most
jacket=$95
skirt=$25

tatuchka [14]3 years ago

3 0

For number 3? I think it's 33 because 33x3= 99 and 99+20= 119.

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a village having a population of 4000, requires 150 litres of water per head per day. it has a tank measuring 20m x 15m x 6m. fo

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<em><u>Solution:</u></em>

Given that, village having a population of 4000, requires 150 litres of water per head per day

<em><u>Let us first find the volume of tank</u></em>

The tank measuring 20m x 15m x 6m

Length = 20 m

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Height = 6 m

$volume\ of\ tank = length \times breadth \times height$

$Volume\ of\ tank = 20 \times 15 \times 6 = 1800$

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<em><u>Therefore, water required for 4000 people per day is:</u></em>

$\rightarrow 4000 \times 150 = 600000 \text{ liters }$

Convert to meters

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<em><u>How many days will the water of this tank last?</u></em>

$\text{Number of days water will last } = \frac{\text{volume of tank}}{\text{total water required per day}}$

$\text{Number of days water will last } = \frac{1800}{600} = 3$

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