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daser333 [38]
3 years ago
15

Subtract −7n+2 ​​from 2n−1 ​. What is the answer? A.−5n+1 B.9n−3 C.9n + 1 D.−9n+3

Mathematics
2 answers:
damaskus [11]3 years ago
8 0

Answer:

9n−3

Step-by-step explanation:

Ludmilka [50]3 years ago
3 0
Make sure that the subtraction is set up in the correct order. We are subtracting -7+2 FROM 2n-1.

(2n-1) - (-7n+2)

Distribute the negative.

(2n-1) + (7n-2)

Combine like terms.

9n - 3

The answer is B.
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The 18 faculty members in a college math department range in age from 32 to 68. A stem plot follows: The first and third quartil
valentina_108 [34]

Answer:

Q_{1}=39, \:and\: Q_{3}=58

Step-by-step explanation:

1) This Stem and Leaf plot works like a Histogram. Completing the question, check below the Stem plot. Look the data out of the Stem plot and within (in the graph below)

32, 34 , 38 , 39 , 39 , 40 , 43 , 45 , 46 , 49 , 53 , 54 , 57 , 58 , 59 , 59 , 63 , 68

2) Notice how the first digit is on the Stem column (check below)

3) To find the first and Third Quartiles

Let's use the formulas to find the position, then the value. As it follows:

Q_3=\frac{3}{4}(n+1) \Rightarrow  Q_3=\frac{3}{4}(18+1) Q_3=14.25 \approx14th =58

Q_1=\frac{(n+1)}{4} \Rightarrow Q_1=4.75 th \approx Q_1 =5th =39

4 0
3 years ago
Your school wants to have 5 computers for every 12 students.There are now 125 computers and 924 students.How many more computers
Oksana_A [137]
First, determine the number of computers that are needed for 924 students.

    n =  (924 students)(5 computers / 12 students)
                 n = 385 computers

Since, there are only 125 computers, the difference can be calculated.
     
       d = 385 computers - 125 computers
   
                d = 260 computers

Hence, 260 more computers are still needed. 
3 0
3 years ago
Which equation shows the substitution method being used to solve the system of linear equations?
bonufazy [111]
B. 
It says x = y + 3. So what they did was put y + 3 in the place of x. 
5 0
2 years ago
Speeeeeeeeeeeeeeeeeeddddddddddddd
kakasveta [241]

0.2 is the answer I believe ^^

6 0
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Consider the words typically associated with geometry. Are there any words that would be hard to precisely define? What words ca
noname [10]

Answer:

Not necessarily words, because there is nothing hard to define in geometry, something hard to LEARN is theorems and postulates though.

Step-by-step explanation:

Hope this helps! :)

8 0
3 years ago
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