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marusya05 [52]
3 years ago
15

Can you help me in rule? I am doing it right?

Mathematics
1 answer:
forsale [732]3 years ago
6 0
The rule would be ~y=4x+3~

Hope this helps

Have a great day/night

Feel free to ask any questions
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What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

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Step-by-step explanation:

The real solution is x = 2:-

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Here  a = x and b = 2 so we have

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To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

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