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3 years ago

7

A restaurant uses 3 pounds of pasta for a party of 14 people. If they are cooking pasta for a party of 56 people, what should th

ey do?

2 answers:

Otrada [13]3 years ago

5 0

Ok first you put 14+14+14+14=56 ok that was 14*4 so you would do 3+3+3+3=12 so 12 is your answer

azamat3 years ago

3 0

If you would like to know how many pounds of pasta the restaurant will need, you can calculate this using the following steps:

3 pounds of pasta ... 14 people
x pounds of pasta = ? ... 56 people

3 * 56 = 14 * x /14
x = 3 * 56 / 14
x = 12 pounds of pasta

The correct result would be 12 pounds of pasta.

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Which fraction has the greatest value?<br> 1/15<br> 1/20<br> 1/10

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1\10 has the greatest value as it is the smallest number diving one

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3 years ago

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A machine makes 600 candies a minute. At this rate, how long will it take this machine to make 1800 boxes, each of which contain

Marta_Voda [28]

1800 boxes with 24 candies each

Total = 1800 * 24 = 43 200 candies

The machine makes 600 candies in 1 minute

   1 candy would take (1/600) minute

   43 200 candies would take 43200 * 1/600 = 72

   = 72 minutes.

Therefore the 1800 boxes would be done in 72 minutes.

3 0

3 years ago

A triangle has points dallas, destination 1, and destination 2. the distance from dallas to destination 1 is 720 miles, and the

timurjin [86]

The distance from the second destination back to Dallas is 918 miles

<h3>Given</h3>

A triangle has points Dallas, destination 1, and destination 2.

The distance from Dallas to destination 1 is 720 miles

The distance from destination 1 and destination 2 is 290 miles

the angle formed between Dallas, destination 1, and destination 2 is 125 degrees.

He moves from destination 1 to Dallas then destination 2

We could use cosine law to find the distance

<h3>What is cosine law?</h3>

The Law of cosines or cosine law means the relation between the length of sides of a triangle with respect to the cosine of its angle. It is also called the cosine rule

$b^{2}=a^2+c^2-2ac*cosB$

= $290^2+720^2-2*720*290*cos125$

=84100+518400-417600 cos 125

=602500-417600*(-0.5735)

=602500+239493.6

=841993.6

b=917.6 miles

≅918 miles

The distance is 918 miles he will fly from the second destination back to Dallas

Learn more on Distance here:

brainly.com/question/23183268

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5 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

The employees of a company were surveyed on questions regarding their educational background (college degree or no college degre

taurus [48]

Answer: D) 0.733.

Step-by-step explanation:

Let C denotes the number of employees having college degree and S denote the number of employees are single.

We are given ,

Total = 600 , n(C)=400 , n(S)=100 , n(C∩S)=60

Then,

$n(C\cup S)=n(C)+n(S)-n(C\cap S)\\\\=400+100-60=440$

Now, the probability that an employee of the company is single or has a college degree is

$P(C\cup S)=\dfrac{n(C\cup S)}{\text{Total}}\\\\=\dfrac{440}{600}=0.733333333\approx0.733$

Hence, the probability that an employee of the company is single or has a college degree is 0.733

8 0

3 years ago