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3 years ago

13

Allison has a poster that is 15“ x 18“ what will the dimensions of the post to be if she scales it down by factor of one over th

ree

1 answer:

qwelly [4]3 years ago

8 0

Answer:

5" by 6"

Step-by-step explanation:

Just multiply each of the dimensions 15" and 18" by 1/3:

5" and 6"

The poster, 1/3 of the original size, will have dimensions 5" by 6".

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A fair rents a thrill ride for $3000. It cost $4 to purchase a token for the ride. Write and solve an inequality to determine th

maria [59]

Answer:

938

Step-by-step explanation:

Given that :

Amount spent by fair on thrill. Ride = $3000

Cost per token of thrill ride = $4

For the fair to make a profit of atleast $750

Then it must realize : (cost of thrill ride + $750) = ($3000 + $750) = $3750

Therefore ;

Cost per token * number of rise tokens ≥ $3750

Let number of ride tokens = x

4x ≥ 3750

4x/4 ≥ 3750/4

x ≥ 937.5

Hence, number of tokens that must be sold = 938

4 0

3 years ago

What is the 9th multiple of 15

MArishka [77]

135 because
15x1=15 15x7=105
15x2=30 15x8=120
15x3=45 15x9=135
15x4=60 15x10=150
15x5=75 15x11=165
15x6=90 15x12=190

5 0

4 years ago

anzhelika [568]

Step-by-step explanation:

they need to add up to -56

and multiply to 180

4 0

3 years ago

Solve the system of equations. Show ALL your work. Put your answer in the form of an ordered pair (x, y)

stiv31 [10]

This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).

6 0

4 years ago

Can someone help me

Lemur [1.5K]

Multiplying fractions is just multiplying the numerators together and the denominators together.

$\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}$

$\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}$

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

$\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}$

Now just compare the numerators to see which one is bigger.

$\sf\dfrac{3}{21}>\dfrac{2}{21}$ therefore, $\sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}$

5 0

4 years ago