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Vikentia [17]
3 years ago
12

2(x + 7) + 3x = 12 What is the first step in solving this equation for x?

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0
First step is expand by using distributive property
<span>2(x + 7) + 3x = 12 

step 1:
2x + 14 + 3x = 12</span>
ehidna [41]3 years ago
5 0
First step would be to expand it and make it 2x + 14 + 3x = 12

Second step would be to add 2x + 14 + 3x so it can be 5x + 14

Third step would be to subtract 14 from both sides

Fourth step would be to subtract 12 - 14 so it can be -2

Last step to get your answer would be to divide both sides by 5

Answer to this whole equation: x = -2/5.
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Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most
romanna [79]

 4x-7\leq 9  inequality could be used to find the number of models Walt builds. Correct option B).

<u>Step-by-step explanation:</u>

Here we have , Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most 9 models. We need to find Which inequality could be used to find the number of models Walt builds . Let's find out:

Let the  the number Walt builds is x , So Dwight builds 7 fewer models than 4 times the number Walt builds i.e.

⇒ 4x-7

But , according to question Dwight builds at most 9 models i.e.

⇒ 4x-7\leq 9

⇒ 4x\leq 16

⇒ \frac{4x}{4}\leq \frac{16}{4}

⇒ x\leq 4

Therefore ,  4x-7\leq 9  inequality could be used to find the number of models Walt builds which is Dwight builds at most 9 and Walt builds at most 4 .

4 0
3 years ago
The sum of three consecutive integers is 108. Which equation would be used to solve this word problem? (HINT: The equation has b
Shtirlitz [24]
3 consecutive integers : x, x + 1, x + 2

x + (x + 1) + (x + 2) = 108...ur equation
3x + 3 = 108...ur equation that has been simplified some
4 0
3 years ago
Read 2 more answers
Does anyone know the answer?
umka21 [38]

Answer: 11/18

Step-by-step explanation: I've attached the explanation

6 0
3 years ago
the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.
marshall27 [118]

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

3 0
3 years ago
HELPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Question in the picture
AVprozaik [17]

Answer:

I think it's still 2.8 because it's a rotation and it's the same shape.

Correct me if I'm wrong

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