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OLga [1]
3 years ago
7

Find the value of x. 43° X x = [?]°

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0
The opposite sides are supplementary
43+x=180
X=137
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Please help! i need this asap
Westkost [7]
Philip equation
ordered data: 3o(oranges), 3g(green), 6y, 8r, 13b(black, 15b(blue
mean: 8 mode: 3 range: 12
8 0
3 years ago
What is the value of x^2 divided by y^4 when x=8 and y=2
7nadin3 [17]

Answer:

4

Step-by-step explanation:

64/16=4

7 0
3 years ago
I don’t understand plzzz help me plzzz
iren [92.7K]
First way: m+7m+m+7m

Second way: m(1+7+1+7) (factorize)

Third way: 2(m)+2(7m)
8 0
4 years ago
Read 2 more answers
You have 2,500 square feet of selling space. You want to reserve at least 125 square feet for each product category you will car
k0ka [10]
If 30% is devoted to aisles, 70% is devloted to merchandise for sale.

That'd come to 0.70(2500 sq ft), or 1750 sq ft.

Create a conversion factor:  125 sq ft = 1 category:
  
                                                                 1 category
                                                becomes --------------------
                                                                  125 sq ft

Muliply this conversion factor by 1750 sq ft.

Result:  1750
             -------- categories = 14 categories.
               125

So you'd have 14 categories and will have allocated 125 sq ft to each; this comes to 1750 sq. ft, which is 70% of the total floor area.  The rest goes to aisles.
7 0
3 years ago
I need help with the Gold-192 and magnitude of the earthquake.<br>​
Mars2501 [29]

Answer:

a. about 18 hrs

a. about 50 times larger

Step-by-step explanation:

"Gold-192 is a radioactive isotope with a half-life of 4.95 hours.  How long would it take for a 25 gram sample of Gold-192 to decay until only 2 grams remain?

The amount A left after time t is:

A = P (½)^(t / T)

where P is the initial amount and T is the half life.

Given A = 2, P = 25, and T = 4.95:

2 = 25 (½)^(t / 4.95)

0.08 = ½^(t / 4.95)

log(0.08) = (t / 4.95) log(0.5)

log(0.08) / log(0.5) = t / 4.95

t = 4.95 log(0.08) / log(0.5)

t ≈ 18

"In May 2015, an earthquake originated in Galesburg, MI had a magnitude of 4.2 on the Richter scale.  In September 2012, a much smaller earthquake originating in Stony Point, MI had a magnitude of 2.5.  The magnitude of an earthquake is given by the formula m = log(I / I₀), where I is the intensity of the earthquake and I₀ is a small reference intensity, how many times larger was the intensity of the Galesburg earthquake compared to the Stony Point earthquake?"

For the Galesburg earthquake:

4.2 = log(I₁ / I₀)

10^4.2 = I₁ / I₀

I₁ = I₀ × 10^4.2

For the Stony Point earthquake:

2.5 = log(I₂ / I₀)

10^2.5 = I₂ / I₀

I₂ = I₀ × 10^2.5

Divide the first equation by the second:

I₁ / I₂ = 10^4.2 / 10^2.5

I₁ / I₂ = 10^(4.2−2.5)

I₁ / I₂ = 10^1.7

I₁ / I₂ ≈ 50

8 0
3 years ago
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