The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
I am assuming the angle is given in degrees.
Answer:
12.71
or in terms of Pi
182π / 45
Steps:
Formula for the arc length:
L = 2πr(θ/360)
We are given r and θ. Let’s solve for L.
L = 2* π * 8 * (92/360)
The answer is 12.71
or in terms of Pi
182π / 45
Answer:
Width just means, diameter.
Step-by-step explanation:
Range is all positive real numbers
answer is D. last one
The awnser is 52 because it’s going up by prime numbers
