Question

Find the equation of the line in slope intercept for that is perpendicular to y=6x-1 and passes through the point (-6,18)

Answer 1

Answer:

y = -x/6 + 17

Step-by-step explanation:

Step 1: find the slope

y = 6x - 1

Equation of a line is

y = mx + c.

m - slope

m = 6

Note : if two lines are perpendicular to the other, both lines are negative reciprocal of each other

m = -1/6

Step 2 : using a point slope form equation

y - y1 = m( x - x1)

( -6 , 18)

x1 = -6

y1 = 18

y - 18 = -1/6(x - (-6)

y - 18 = -1/6( x + 6)

y - 18 = -x - 6 / 6

y = (-x - 6)/6 + 18

LCM = 6

y = (-x - 6 + 108)/6

y = -x + 102 / 6

y = -x/6 + 102/6

y = -x/6 + 17

The equation of the line is

y = -x/6 + 17