Ask question

Ask question

All categories

MA_775_DIABLO [31]

3 years ago

10

A car is traveling at a rate of 44 feet per second. What is the cats rate in miles per hour? How many miles will the car travel

in 4 hours? 1 mile = 5280 feet. Do not round.

1 answer:

Citrus2011 [14]3 years ago

6 0

It takes 3600 seconds for one hour. It takes 14400 seconds for four hours.

Hope I helped!

You might be interested in

Your car can drive 300 miles on a tank of 15 gallons. How far can it drive on 40<br> gallons?

Flura [38]

Answer:

800

Step-by-step explanation:

since 300 divided by 15 is 20.

20 x 40= 800

3 0

3 years ago

Read 2 more answers

Find three solutions of the equation y=9x-4?

Bas_tet [7]

<span>answer
A) (-5,-49),(-2,-22),(3,23)

</span>when x = - 5 ; y=9x-4 = 9(-5) -4 = -49
when x = - 2 ; y=9x-4 = 9(-2) -4 = -22
when x = 3 ; y=9x-4 = 9(3) -4 = 23

6 0

3 years ago

Read 2 more answers

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

Help please and ty ! (no its not 388)

jeka94

It is 484 I knwonir

5 0

3 years ago

Read 2 more answers

化學製程中溫度的影響為研究化學製程中溫度對產量之影響，我們在 3 種溫度下各生產 3批產品，結果如下表。請建立 ANOVA 表。在 0.05 顯著水準檢定不同的溫度是否會影響平均產量。

fiasKO [112]

Answer:

Step-by-step explanation:

產品 1 14 20 13

產品 2 15 11 18

產品 3 12 15 16

8 0

3 years ago