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Olenka [21]
3 years ago
11

Question: (-11x-11x-11)=?

Mathematics
1 answer:
lakkis [162]3 years ago
4 0

Answer:

-22x-11

Step-by-step explanation:

Your welcome! :)

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What are the weight of the horses on the farm? Is that a statistical question?
Marizza181 [45]
Based on my information, I believe that this would actually be a statistical because the question contains extra information that would help you narrow down the answer. The question could have been a lot easier, such as: "how much do horses weigh", but it does not, it
contained extra data that would help answer the question to the point.
5 0
3 years ago
How do you change 1/4 to a decimal
iogann1982 [59]
1.00 is 1, you may know how quarters work, four equal a dollar, one quarter is 25 cents, 4 are one dollar, 1/4, or one diveded by 4, is 0.25
7 0
3 years ago
2p + 7p = 54 <br> Need to share more work
Alexeev081 [22]

Answer:

p=6

Step-by-step explanation:

2p + 7p = 54

Combine like terms

9p = 54

Divide by 9

9p/9 = 54/9

p = 6

3 0
3 years ago
Read 2 more answers
What is the ordered pair solution to the system y= -4x and y=2x+12 ??
german

Answer:

The ordered pair solution is (-2, 8)

Step-by-step explanation:

y = -4x ------ equation 1

y = 2x + 12 ---- equation 2

We solve for x by substitution;

Substituting the value of y into equation 2;

y = 2x + 12

-4x = 2x + 12

-4x -2x = 12

-6x = 12

Divide by -6

x = 12/(-6)

x = -2

From equation 1;

y = -4x

Substituting the value of x;

y = -4×(-2)

y = 8.

PROOF;

y = -4x

8 = -4*(-2)

8 = 8

4 0
4 years ago
Please help me with 1,2,3,4 and show me how you get it the answers
Dafna11 [192]

Answer:

Step-by-step explanation:

Use the formula of distance between the two points (x_1,y_1) and (x_2,y_2),

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

1. Distance between A(3, 4) and B(8, 12),

  AB = \sqrt{(8-3)^2+(12-4)^2}

  AB = \sqrt{25+64}

        = \sqrt{89}

        ≈ 9.43

2. Distance between C(-2, 10) and D(3, -2),

   CD = \sqrt{(3+2)^2+(-2-10)^2}

         = \sqrt{25+144}

         = \sqrt{169}

         = 13.00

3. Distance between X(20, 4) and Y(17, 0),

    XY = \sqrt{(20-17)^2+(4-0)^2}

          = \sqrt{3^2+4^2}

          = \sqrt{25}

          = 5.00

4. Distance between E(2, -1) and M(6, 9),

    EM = \sqrt{(2-6)^2+(-1-9)^2}

          = \sqrt{16+100}

          = \sqrt{116}

          = 10.77

8 0
3 years ago
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