Got you. So we will use the basic formula for the area of a rectangle and insert variable values. (^_^)
Area= Width(Height) ----------- Insert values of width and height [width = (x-1)
, height = (x+9)]
Area= (x-1)(x+9) ) -------------- Then expand if needed?
= x² +8x -9
Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
9514 1404 393
Answer:
- Ram -- ₹1200
- Kalpana -- ₹800
Step-by-step explanation:
Their age total is 15+10=25, so Ram will get 15/25 = 0.6 of the total. Kalpana will get the remaining 0.4 of the total.
Ram receives 0.6 × ₹2000 = ₹1200
Kalpana receives 0.4 × ₹2000 = ₹800
Answer:
(4, 80) Which is L
Step-by-step explanation:
First number should be on the X axis and the second on the Y axis.
