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Ivanshal [37]
3 years ago
10

What is the equation of the circle with center (-3.2,2.1) and radius 4.3?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
8 0
(x+3.2)^2+(y-2.1)^2=4.3^2
marissa [1.9K]3 years ago
8 0

Answer:

(x+3.2)^2+(y-2.1)^2=(4.3)^2

Step-by-step explanation:

It is given that the center of the circle is (-3.2,2.1) and radius is 4.3.

Now, the equation of the circle with center (a,b) and the radius 'r' is represented as:

(x-a)^2+(y-b)^2=r^2

Now, the given center is (-3.2,2.1) and radius is 4.3, thus the equation of the circle becomes,:

(x-(-3.2))^2+(y-2.1)^2=(4.3)^2

(x+3.2)^2+(y-2.1)^2=(4.3)^2

Which is the required equation.

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