Given f(x) = x^2+4, does there exist an x-intercept between [-2, 3]. Why or why not. Be sure to include in your discussion the I ntermediate Value Theorem
1 answer:
The x-intercepts are the values of x for which f(x) = 0. x^2 + 4 = 0 x^2 = -4 x= ±√(-4), which are not real numbers. f(x) does not have an x-intercept.
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