Answer:
their are 4 weeks in a month so 4*7=
28
so its 1/28 which is equals to (1 divided by 28)
3.57%
Hope This Helps!!!
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
84 c. –25 6. 119 7. –28 36 8a. 4 b. 52 LESSON EI.B: ANSWERS 709 Topic EI .... The length is 11 inches, and the width is 7 inches. ... 15x – 10 = 2x + 6 1 5 10. x = 1 11. y = 8x – 5 12. x = y + 8 8 49. .... 5xy 3 – 17x 2y + 8xy + 16x 3y – 7x 10. x 3y 2z – 10x 2y + 14x 2z + 3xy 2 – 25xz 2 LESSON ... 2 > y > –5 F a 4x 3 y 5 4y 3 x 22.
Step-by-step explanation:
Answer:
<h3>Find the explanation below</h3>
Step-by-step explanation:
A) Given the equation z - 5 = 2
To get the solution, we will add 5 to both sides and find z as shown;
z - 5 = 2
z - 5 + 5 = 2 + 5
z + 0 = 2+5
z = 7
Hence z = 5 is not the solution of the equation but z = 7
B) Given the inequality expression t+2>5
Substract 2 from both sides of the equation;
t+2 - 2>5 - 2
t + 0> 3
t>3
Hence the solution t = 4 is not true for the expression. The solution is t > 3
C) Given the expression x-2=2, to get the solution to the expression, you will add 2 to both sides of the equation;
x - 2+ 2 = 2 + 2
x + 0 = 4
x = 4
Therefore x = 4 is the solution of this equation.
Based on the question, only Option C is correct
Idk I'm learning that also