A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
Answer:
C) 175.84 cubic feet
Step-by-step explanation:
V=πr^2h is the formula I used
I plugged in the numbers and solved
Answer:
add 1/4 to each side
Step-by-step explanation:
x^2+x=11
We take the coefficient of the x term
1
Then divide it by 2
1/2
Then square it
(1/2) ^2 = 1/4
Add this to both sides of the equation
x^2 + x + 1/4 = 11+1/4
(x+1/2)^2 = 11 1/4
So you would just have to divide 20/7 to get the percentage of it.
The answer would be 2.85%.
