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Hatshy [7]
3 years ago
13

PLEASE HELP ME SOLVE THIS ASAP.

Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer: (10, -1)

Step-by-step explanation:

Subtract the bottom equation from the top to get:

2x=20

X=10

Plug on for X , y= -1

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the value of a car is 28,000 bit it is depreciating 12% per year how much will the car be worth in 8 years
dexar [7]

Answer:

Hello,

10,070

Step-by-step explanation:

100% - 12% = 88% = 0.88

28,000 x 0.88^8 = 10,069.76...

7 0
3 years ago
Cathleen ran a total of 16 miles. She ran exactly 2 2/3 miles each day. How many days did it take her to run 16 miles
kirill [66]
It took her 6 days. 2 and 2/3 times 6 equals 16
6 0
3 years ago
On Monday, Anya read 11 pages of a book in 30 minutes. On Tuesday, she read 18 pages in 45 minutes. Did Anya's reading speed inc
Genrish500 [490]
Yes 
11 diveded by 30 equals 61%
30 divided by 45 equals 66%

the average of 61% and 66% is more then 50%

8 0
3 years ago
A video game company surveys a random sample of 225 of its best customer and finds that the average gamer spends $606 a year on
victus00 [196]

Answer:

Multi facets

Step-by-step explanation:

First company surveys best customers so they are highest spending

First company standard deviation is high @ $62 so their spends are $606 a year plus or minus $180 (rounded up)

Second company has a Random sample so includes all customers

Second company has larger number of responses

Second company has a range of plus or minus $40

6 0
3 years ago
A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
3 years ago
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