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maks197457 [2]
4 years ago
7

Brent made the table shown to discribe two different relationships between animals.

Physics
1 answer:
grigory [225]4 years ago
5 0

i think it is the second one due to the preditory descritpion of relationship A


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Suppose you have an object tied to a rope and are rotating it over your head in uniform circular motion. If you increase the len
emmainna [20.7K]

Answer:

Centripetal Acceleration

In the previous section, we defined circular motion. The simplest case of circular motion is uniform circular motion, where an object travels a circular path at a constant speed. Note that, unlike speed, the linear velocity of an object in circular motion is constantly changing because it is always changing direction. We know from kinematics that acceleration is a change in velocity, either in magnitude or in direction or both. Therefore, an object undergoing uniform circular motion is always accelerating, even though the magnitude of its velocity is constant.

You experience this acceleration yourself every time you ride in a car while it turns a corner. If you hold the steering wheel steady during the turn and move at a constant speed, you are executing uniform circular motion. What you notice is a feeling of sliding (or being flung, depending on the speed) away from the center of the turn. This isn’t an actual force that is acting on you—it only happens because your body wants to continue moving in a straight line (as per Newton’s first law) whereas the car is turning off this straight-line path. Inside the car it appears as if you are forced away from the center of the turn. This fictitious force is known as the centrifugal force. The sharper the curve and the greater your speed, the more noticeable this effect becomes.

Figure shows an object moving in a circular path at constant speed. The direction of the instantaneous tangential velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity; in this case it points roughly toward the center of rotation. (The center of rotation is at the center of the circular path). If we imagine Δs becoming smaller and smaller, then the acceleration would point exactly toward the center of rotation, but this case is hard to draw. We call the acceleration of an object moving in uniform circular motion the centripetal acceleration ac because centripetal means “center seeking.”

Explanation:

8 0
3 years ago
Why are nuclear power plants controversial
VashaNatasha [74]
I would have to say because while they do produce relatively clean power, it is extremely dangerous and overly harmful should one "melt down." Some people believe the reward is worth the risk, others do not. It is more a matter of perspective - are you near the nuclear power plant or not? If you are, chances are you won't like it - on the other hand, if you are not right hear the power plant you might like it more. I hope this helps!

P.S. - If you think I did a good job I would love it if you went to my YouTube channel to see if I can help you more there. I am just starting out and don't have much time to record, but I would love to have some user-submitted topics! Here is the link: https://www.youtube.com/channel/UCG0zQcSsxZ2mu-OnZRdI2-Q. I hope to see you there!
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3 years ago
What happens when an electron moving from the 3rd energy level to the 1st energy level?
Sholpan [36]

Answer:

A photon of wavelength 103 nm is released

Explanation:

When an electron in an atom jumps from a higher energy level to a lower energy level, it releases a photon whose energy is equal to the difference in energy between the two levels.

For example, if we are talking about a hydrogen atom, the energy of the levels are:

E_1 = -13.6 eV\\E_2 = -3.4 eV\\E_3 = -1.5 eV

So, the energy of the photon released when the electron jumps from the level n=3 to n=1 is

\Delta E = E_3 - E_1 = -1.5 -(-13.6)=12.1 eV

In Joules,

\Delta E =12.1\cdot 1.6\cdot 10^{-19} = 1.94\cdot 10^{-18} J

We can also find the wavelength of this photon, using the equation:

\Delta E = \frac{hc}{\lambda}\rightarrow  \lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{1.94\cdot 10^{-18}}=1.03\cdot 10^{-7} m = 103 nm

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4 years ago
An easy 20 points + brainiest.
Papessa [141]

Answer:

Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, Milky Way ;-;

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2 years ago
Is the following research description experimental, descriptive, or applied?
Bingel [31]

Answer:

It is experimental. She will testing or investigating on children. So yeah, it is experimental

7 0
3 years ago
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