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4 years ago

7

Brent made the table shown to discribe two different relationships between animals.

1 answer:

grigory [225]4 years ago

5 0

i think it is the second one due to the preditory descritpion of relationship A

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How many significant figures are in 246.32

muminat

Answer:5

Explanation:

Decimal :2

Significant notation :2.4632× 10^2

8 0

4 years ago

A 2200-kg railway freight car coasts at 4.1 m/s underneath a grain terminal, which dumps grain directly down into the freight ca

777dan777 [17]

Answer:

The answer is " $2.41 \times 10^3$ "

Explanation:

Given:

$m_i = 2000 \ kg \\\\v_i= 4.1 \ \frac{m}{s} \\\\v_f = 3.4 \ \frac{m}{s} \\$

Using formula:

$\to m_iv_i = m_fv_f \\\\\to m_f= \frac{m_iv_i}{v_f}$

$p_i, p_f$ = system initial and final linear momentum.

$V_i, v_f$ = system original and final linear pace.

$m_i$ = original weight of the car freight.

$m_f$ = car's maximum weight

$= \frac{ 2000 \times 4.1}{3.4}\\\\= \frac{ 8.2\times 10^3}{3.4}\\\\= 2.41 \times 10^3$

$\boxed{m_f = 2.41 \times 10^3}$

8 0

3 years ago

Question 36 pls<br> Physics

Lera25 [3.4K]

$R=\frac{U}{I}=\frac{0.5V}{180\cdot10^{-6}A}\approx2.78k\Omega$

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3 years ago

Draw a diagram of a seismometer showing how the movement of earth is lated into a siesmogram

MakcuM [25]

I’ll explain this to you draw a diagram of seismometer show how the earth moves it’s round and it moves on it axis and spins fully which takes it a year 365 days

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3 years ago

Read 2 more answers

The Density of a liquid is 1.0g/cm³. What is its density in kg/m? Show your workings clearly.

Ipatiy [6.2K]

Answer:

$\displaystyle 1 \frac{gr}{cm^3}=1,000\frac{kg}{m^3}$

Explanation:

Note: We are assuming the unit 'm' is 'm^3' to be compatible with the given unit.

<u>Unit Conversions </u>

Is the procedure followed to change the units of a certain magnitude to other units of the same magnitude. Example: centimeters to meters, hours to minutes, Kg to gr.

When dealing with composite units, each unit must be converted separately.

The density of some liquid is

$\displaystyle 1 \frac{gr}{cm^3}$

We are required to convert to $Kg/m^3$ , so we convert separately

We know that

$\displaystyle 1 gr=\frac{1}{1000}Kg$

$\displaystyle 1 cm^3=\frac{1}{1,000,000}m^3$

The conversion is

$\displaystyle 1 \frac{gr}{cm^3}=\frac{\frac{1}{1000}Kg}{\frac{1}{1,000,000}m^3}$

$\displaystyle 1 \frac{gr}{cm^3}=\frac{1,000,000\ kg}{1000\ m^3}=1,000\frac{kg}{m^3}$

Thus

$\boxed{\displaystyle 1 \frac{gr}{cm^3}=1,000\frac{kg}{m^3}}$

6 0

3 years ago