Answer: Approximately 22 cm
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Explanation:
The unstretched spring is 12.0 cm long. When adding a load of 5.0 N, it stretches to 15.0 cm. This is a displacement of 15.0 - 12.0 = 3.0 cm, which is the amount the spring is stretched.
Convert this displacement to meters (so that it fits with the meters unit buried in Newtons).
3.0 cm = (3.0)/100 = 0.03 m
Apply Hooke's Law to find the spring constant k
F = -kx
5.0 = -k*(0.03)
k = -(5.0)/(0.03)
k = -166.667 approximately
Now we must find the displacement x when F = 15 newtons
F = -kx
-kx = F
x = F/(-k)
x = -F/k
x = -15/(-166.667)
x = 0.089 approximately
x = 0.1
The displacement to one decimal place is about 0.1 meters, which converts to 100*0.1 = 10 cm
So the spring will be stretched to about 12cm+10cm = 22 cm
It depends upon the type of graph that you are talking about,
If the graph is Velocity - Time graph, then time lies on the X axis and speed on the Y axis.
If it is Distance - Time graph, the time lies on the X axis and distance on the Y axis.
But generally, it is ALWAYS TIME IN THE ‘X’ AXIS AND DISTANCE ON THE ‘Y’ AXIS.
Let me know if you have any doubts by either commenting or messaging me
Answer:
Magnetic force, 
Explanation:
It is given that,
Magnetic field, B = 2 T
Velocity of the proton, v = 300 m/s
Charge on the proton, 
The magnetic field is oriented perpendicular to the proton’s velocity. The magnetic force on the charged particle is given by :
The magnetic field is oriented perpendicular to the proton’s velocity, 
So, the magnitude of the force that the proton experiences while it moves through the magnetic field is 
. Hence, this is the required solution.
A. The IV is the temperature of gas in the balloon.
B. The DV is the volume of the balloon.
This is because the temperature of the gas is the variable being manipulated in the experiment (Independent) and the volume is changing based on the shifts of the temperature (thus volume is Dependent).
