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3 years ago

Why are nuclear power plants controversial

1 answer:

8 0

I would have to say because while they do produce relatively clean power, it is extremely dangerous and overly harmful should one "melt down." Some people believe the reward is worth the risk, others do not. It is more a matter of perspective - are you near the nuclear power plant or not? If you are, chances are you won't like it - on the other hand, if you are not right hear the power plant you might like it more. I hope this helps!

P.S. - If you think I did a good job I would love it if you went to my YouTube channel to see if I can help you more there. I am just starting out and don't have much time to record, but I would love to have some user-submitted topics! Here is the link: https://www.youtube.com/channel/UCG0zQcSsxZ2mu-OnZRdI2-Q. I hope to see you there!

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A radioactive decay is illustrated. Which radioactive emission is a product of this decay?

hram777 [196]

The radioactive decay is shown in the image attached to this answer

Answer:

Alpha

Explanation:

An alpha decay is said to have occurred when the mass number of the daughter nucleus decreases by four units and the atomic number of the daughter nucleus decreases by two units.

If we look at the equation from left to right, we will notice that the mass number of the daughter nucleus decreased by four units and the atomic of the daughter nucleus number by two units compared to that of the parent nucleus leading to the emission of an alpha particle.

5 0

3 years ago

The volume of an ideal gas is held constant. Determine the ratio P2/P1 of the final pressure to the initial pressure when the te

cluponka [151]

<h2>Answer:</h2>

(a) P₂ / P₁ = 2 / 1

(b) P₂ / P₁ = 17.93 / 13

<h2>Explanation:</h2>

At constant volume, the pressure (P) of an ideal gas is directly proportional to its temperature (T) as stated by Joseph Gay-Lussac. i.e

P ∝ T

=> P = KT

=> P / T = K

=> (P₁ / T₁) = (P₂ / T₂) = K

=> (P₁ / P₂) = (T₁ / T₂) = K

=> (P₂ / P₁) = (T₂ / T₁) = K -----------------------(i)

Where;

P₁ and P₂ are the initial and final pressures of the gas.

T₁ and T₂ are the initial and final temperatures of the gas.

(a) if temperature rises from 39 to 78 K;

This implies that;

T₁ = 39 K

T₂ = 78 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (78 / 39)

=> (P₂ / P₁) = (26 / 13)

=> (P₂ / P₁) = (2 / 1)

Therefore, the ratio P₂ / P₁ = 2 / 1

(b) if temperature rises from 39.0 to 53.8 K;

This implies that;

T₁ = 39.0 K

T₂ = 53.8 K

Substitute these values into equation (i) as follows;

=> (P₂ / P₁) = (53.8 / 39)

=> (P₂ / P₁) = (17.93 / 13)

Therefore, the ratio P₂ / P₁ = 17.93 / 13

3 0

3 years ago

What are the three most important types of units in radiobiology? Explain the meaning of each.

Rom4ik [11]

Answer:

Most adverse health effects of radiation exposure may be grouped in two general categories:

deterministic effects (harmful tissue reactions) due in large part to the killing/ malfunction of cells following high doses; and

stochastic effects, i.e., cancer and heritable effects involving either cancer development in exposed individuals owing to mutation of somatic cells or heritable disease in their offspring owing to mutation of reproductive (germ)

4 0

3 years ago

You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f

Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

$u = 0m/s$

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

$s = ut+\frac{1}{2} at^2$

Replacing,

$1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2$

$u =6.4013m/s$

The height of the acorn above the meter stick can be calculated as,

$v^2 = u^2 +2gh$

$h = \frac{v^2-u^2}{2g}$

$h = \frac{6.4013^2-0^2}{2(9.8)}$

$h = 2.0906m$

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

$h = 2.0906+1.87$

$h = 3.9606m$

4 0

4 years ago

An alert physics student stands beside the tracks as a train rolls slowly past. He notes that the frequency of the train whistle

Dovator [93]

Answer:The velocity of the train is 3.84m/s

Explanation:

According to the Doppler effect, if the source is moving towards you then the apparent frequency of the sound emitted by the source is higher and if the source is moving away from you then the apparent frequency of the sound emitted by the source is smaller.

This is given by:

fo = V +-Vo/ V +-Vo × source

Where fo= observed frequency

V= velocity of sound

Vo= vo it of the observer

fsource= frequency the source

Given:

Observed frequency of the approaching train fo1= 452Hz

The observed frequency of train= fo2= 442Hz

Velocity of sound= 334m/s

Velocity of source=?

Train approaching the observer is given by:

fo1= V/(V - Vs)× source ...eq1

Train passes the student is given by:

fo2= V/(V - Vs)×source ...eq2

Divide eq1 by eq2

452/442 = (343+Vs)/(343 - Vs)

1.02 =(343+Vs)/(343 -Vs)

Cross multiply

1.02(343- Vs) = 343 + Vs

350.76 - 1.02Vs = 343 + Vs

Collecting like terms

350.76 -343= 1.02Vs+ Vs

7.76 = 2.02Vs

Vs= 7.76/2.02

Vs= 3.84m/s

4 0

3 years ago