The magnitude and direction (inward or outward) of the net flux through the cell boundary is - 0.887 wb.m².
<h3>
What is flux?</h3>
Flux describes any effect that appears to pass or travel through a surface or substance.
The magnitude and direction (inward or outward) of the net flux through the cell boundary is calculated as follows;
Ф = Q/ε
where;
- Q is net charge
- ε is permittivity of free space
Φ = (-7.85 x 10⁻¹²)/(8.85 x 10⁻¹²)
Φ = - 0.887 wb.m²
Learn more about flux here: brainly.com/question/10736183
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Answer:
Use the ammeter to measure the current that flows through each wire, because a larger current that flows through the wire corresponds to a smaller resistivity
Explanation:
Since they are connected to a constant voltage power source, the potential difference does not change. The potential difference is proportional to the product of the current and the resistance and, the resistance opposes the flow of electric current. It is clear to see that a large current that flows through the current means there is a lesser resistance to the flow of current at constant potential difference across the circuit.
Answer:
Image distance of apple=-6.7 cm
Magnification of apple=0.33
Explanation:
We are given that an apple is placed 20.cm in front of a diverging lens.
Object distance=u=-20 cm
Focal length=f=-10 cm
Because focal length of diverging lens is negative.
We have to find the image distance and magnification of the apple.
Lens formula
![\frac{1}{f}=\frac{1}{v}-\frac{1}{u}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%3D%5Cfrac%7B1%7D%7Bv%7D-%5Cfrac%7B1%7D%7Bu%7D)
Substitute the values then we get
![-\frac{1}{10}=\frac{1}{v}+\frac{1}{20}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B10%7D%3D%5Cfrac%7B1%7D%7Bv%7D%2B%5Cfrac%7B1%7D%7B20%7D)
![\frac{1}{v}=-\frac{1}{10}-\frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D%3D-%5Cfrac%7B1%7D%7B10%7D-%5Cfrac%7B1%7D%7B20%7D)
![\frac{1}{v}=\frac{-2-1}{20}=-\frac{3}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bv%7D%3D%5Cfrac%7B-2-1%7D%7B20%7D%3D-%5Cfrac%7B3%7D%7B20%7D)
![v=-\frac{20}{3}=-6.7 cm](https://tex.z-dn.net/?f=v%3D-%5Cfrac%7B20%7D%7B3%7D%3D-6.7%20cm)
Image distance of apple=-6.7 cm
Magnification=m=![\frac{v}{u}=\frac{-\frac{20}{3}}{-20}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Bu%7D%3D%5Cfrac%7B-%5Cfrac%7B20%7D%7B3%7D%7D%7B-20%7D)
Magnification of apple=![\frac{1}{3}=0.33](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%3D0.33)
Hence, the magnification of apple=0.33
Neglecting friction and air resistance, the first hill must be built 4 times higher than it is now.