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borishaifa [10]
3 years ago
14

The dimensions of a closed rectangular box are measured

Mathematics
1 answer:
Damm [24]3 years ago
6 0

Answer:

The maximum error in  calculating the surface area of the box is 152 square cm.

Step-by-step explanation:

We are given the following information in the question:

The dimensions of a closed rectangular box are measured  as 80 cm, 60 cm, 50 cm, respectively.

Possible error = 0.2 cm

Surface area of rectangular box =

S = 2(lb + bh + lh)

where l, b and h are the length, breadth and height of the rectangular box respectively.

Change in area =

\Delta S \approx dS = 2(l\Delta b + b\Delta l + b\Delta h + h\Delta b + l\Delta h + h\Delta l)\\

Putting the values, we get,

Change in area =

=2(\Delta l (b+h) + \Delta b (h+l) + \Deltah(l + b))\\=2(0.2(110) + 0.2(130) + 0.2(140))\\= 152\text{ square cm}

The maximum error in  calculating the surface area of the box is 152 square cm.

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1. a. The domain of the function in the context of this problem is h ≥ 0. The maximum value of h will correspond to the time at which the concentration is considered to be negligible. If that time is when the concentration decays to 1% of its peak value, then perhaps the suitable domain is 0 ≤ h ≤ 180.

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2. As h gets large the value of the function approaches 2/h, which is to say the horizontal asymptote is C = 0. It means the concentration of medication in the blood eventually decays to zero.

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3. C(0) = 0 is the only intercept in the domain of the function. (h, C(h)) = (0, 0)

In the context of this problem, it means the blood concentration of medication is zero at the time of the injection.

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4. About 1.95 hours after injection, a maximum concentration of the drug occur in the bloodstream. This value is easily found using a graphing calculator.

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