Answer:
3 3/8
Step-by-step explanation:
Correct me if I'm wrong
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Answer:
answer is
{X^2 + 4, X<2
{X + 4, X>2
Step-by-step explanation:
Because both solution set graph is at the begining hole at the value of X = 2 this means both sets doesn't contain 2.
Answer:
1 and 3 is right and I’m pretty sure 2 is right also.
Step-by-step explanation:
Answer:
slope = -1.5
Step-by-step explanation:
A set of three or more points are said to be collinear if they all lie on the same straight line.
We have been given the following collinear set of points;
P(0, 3), Q(2, 0), R(4, -3)
This implies that P, Q, and R lie on the same line.
The slope of a line is defined as; (change in y)/(change in x)
Using the points P and Q, the slope of the line is calculated as;
(0-3)/(2-0) = -3/2 = -1.5