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swat32
3 years ago
7

One zero of the polynomial function f(x) = x3 + x2 + 20x is x = 0. What are the zeros of the polynomial function?

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

given polynomial function

f(x) = x³ + x² + 20 x ....................(1)

x³ + x² + 20 x = 0

so, to find the zeroes we can use options to get the answer.

As roots will satisfy the equation now what we will do to get the answer is put the value in the polynomial.

At x = 0      f(x) = 0 hence zero will be the one of the zeroes of the problem

At x= 5     f(x) = 5³ + 5² + 20 × 5 = 250 hence 5 will not be the root.

At x= -5    f(x)  = -5³ + -5² + 20 × -5 = -200  hence -5 will also not be the root of the polynomial.

hence, we can clearly say that there is no option which will satisfy.

So, the option correct is none of these.

daser333 [38]3 years ago
6 0

Answer:

The correct option is C

Step-by-step explanation:

if f(x)= x3 + x2 - 20x

Replace f(x) by y

y = x3 + x2 - 20x

0 =x3 + x2 - 20x

x3 + x2 - 20x = 0

Take out x as a common:

x(x2+x-20)=0

Find factors of x2+x+20.

x(x^2+4x-5x-20) = 0

x{x(x+4)-5(x+4)}=0

x(x+4)(x-5)=0

Set x= 0

x=0 , x+4=0 , x-5 =0

x=0, x=0-4 , x=0+5

x=0, x= -4, x=5

x=(0,5,-4)

The correct option is C....

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90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

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n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h  ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

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c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

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