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Novosadov [1.4K]
4 years ago
5

A ship travels due west for 90 miles and turns to travel 80 miles in the northwest direction at a 120 degree angle. How far is t

he ship from its original position
Mathematics
1 answer:
adoni [48]4 years ago
6 0
We breakdown the components of the distances.
(1) 90 miles west.
                          x - component = -90 miles
                          y - component = 0 miles
(2) 80 miles, northwest (120°)
                          x - component = (80 miles)*(sin 30°) = 40 miles (negative)
                          y - component =(80 miles)*(cos 30°) = 69.282 miles (positive)

Solve for the distance,
                                 √(-90 - - 40)² + (69.282 miles)²  = <em>147.31 miles</em>
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8j - \frac{3q}{2} - \frac{18}{5}

Step-by-step explanation:

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2 years ago
Describe Cullen's mistake
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Answer:Cullen did not add 4n to the -6n he added -4n.

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An angle measures 70° more than the measure of its supplementary angle. What is the measure of each angle
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Answer:

55° and 125°

Step-by-step explanation:

Formulate an equation x + (x+70) = 180

Combine like terms to get 2x + 70 = 180

Subtract 70 on both sides to get 2x = 110.

Divide both sides by 2 to get x = 55.

Add 70 to 55 to get 125.

Check your answer by adding 55 + 125. It equals 180, so the angles are equal to 55 and 125.

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3 years ago
There are 4 teams in a soccer tournament. Each team plays each of the other teams exactly once. In each match, the winner receiv
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Answer:

8 points

Step-by-step explanation:

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0: 3 lost

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2: 2 tied, 1 lost

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4: 1 won, 1 lost, 1 tied

5: 1 won, 2 tied

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3 0
3 years ago
C. Make n subject of the formula<br>S= n/2 [2a + (n - 1)d]<br><br>please provide your working out ​
yKpoI14uk [10]

Answer:

n=\frac{4as -2ds}{(1-2ds)}

Step-by-step explanation:

S= \frac{n}{2 [2a + (n - 1)d]}

Simplifying the fraction by multiplying d into the (n-1) term,

s=\frac{n}{2 [2a + (n - 1)d] } = \frac{n}{2[2a + dn - d] }

Simplifying the fraction by multiplying 2 throughout,

s= \frac{n}{4a + 2dn-2d}

Multiply (4a + 2dn-2d) on both sides

(4a + 2dn-2d)s= \frac{n}{4a + 2dn-2d} (4a + 2dn-2d)

Cancel the (4a + 2dn-2d) on the right hand side

(4a + 2dn-2d)s= n

Multiply s to the terms,

4as + 2dns-2ds= n

Move 2dns to the right hand side by subtracting 2dns on both sides4as + 2dns-2ds-2dns= n-2dns

4as -2ds= n-2dns

On the right hand side of the equation, take out n

4as -2ds= n(1-2ds)

Divide Left hand side by (1-2ds),

n=\frac{4as -2ds}{(1-2ds)}

6 0
3 years ago
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