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3 years ago

The measures of Zx and Zy are equal. Which is the value of m?

Mathematics

1 answer:

Ede4ka [16]3 years ago

3 0

Z because y=Mx+b so whatever is before x is the answer in this case it’s z

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Need help on this problem

trasher [3.6K]

The answer to the question

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3 years ago

Can someone help me

ICE Princess25 [194]

Answer:

S=49

Step-by-step explanation:

Any triangle has an interior angle of 180.

So just add them up and set the sum equal to 180 degrees.

2s+s+33=180

3s=180-33

3s=147 . Divide both sides by 3 to isolate variable s

s=49

7 0

2 years ago

Read 2 more answers

PLEASE MAKE SURE HELP ME!

bulgar [2K]

Answer:

1. The first problem is wrong, it should be 0.5(3(15) + 2(20)) because the parentheses make sure that every purchased item is being divided by 2 (multiplying by 0.5 is the same as dividing by 2)

2. The second problem is partially correct. The first two answers you have checked are correct, but the last one is wrong. The third answer should be 6 + 12 instead because that's just a simplified version of 2(3) + 6(2), meaning they are equal

3. I cannot read your answers in the "Why or Why Not" column in the third problem, but the answers you gave in the "Evaluate" and "Does It Work?" columns are all correct.

7 0

3 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!