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Burka [1]
4 years ago
7

When you have 6 significant numbers and want to get 9 what do you do

Mathematics
2 answers:
Leno4ka [110]4 years ago
8 0
I think u add not sure though
maw [93]4 years ago
7 0
I think you need to add
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Y=-3 - x, how to draw the graph​
adell [148]

Answer: See attachment below (graphing)

Step-by-step explanation:

<u>INFORMATION:</u>

The slope-intercept is when y=mx+b

mx=the slope

b=y-intercept

<u />

<u>REPHRASE EQUATION:</u>

y=mx+b

y=-3-x

y=(-1)x-3

<u>CONCLUSION:</u>

Slope=-1

Y-intercept=-3

Hope this helps!! :)

Please let me know if you have any questions

6 0
3 years ago
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ANSWER NOW PLEASE.Solve this system of equations with substitution<br><br> x = y - 4<br><br> 2y = x
Arada [10]
In points form the answer is (-8,-4) and in equation form the answer is x=-8, y=-4
If this answered help you then please consider marking it as brainliest to help me level up to expert
4 0
3 years ago
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Which radical expression in the picture is equivalent to t^5/8?
mixas84 [53]
<h3>Answer: Choice B</h3>

=========================================================

Explanation:

The rule we use is

\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m

where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).

So for instance,

\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3

or in this case,

\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5

5 0
3 years ago
I'm completely lost. I don't know how to start the question. Can you help me ?
BaLLatris [955]
The answer is D 13/28.
8 0
4 years ago
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Start solving #2 with the substitution method
Brums [2.3K]

Answer:

A=3, B =3, C = 3

Step-by-step explanation:

9/3 (the letters) = 3 Each

3 - 24 - 3 = -27

2a = 6

6 - 3 + 3 = 6

A, b, c, all equal 3.

7 0
3 years ago
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