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mixer [17]
3 years ago
5

If m ∆ n means m²-2mm+n³, determine the value of 3∆2.​

Mathematics
2 answers:
Novay_Z [31]3 years ago
6 0

\large\underline{\underline{ \sf\maltese Correct \ Question :- }}

If m ∆ n means m²-2mm+n², determine the value of 3∆2.

\large\underline{\underline{ \sf\maltese Answer :- }}

Here we are given that m ∆ n means m² -2mn +n². And we need to find the value of 3∆2 . So let's find out what does the " ∆ " operator does.

Here we can see that m² - 2mn - n² is the whole square of ( m - n)² . A inference can be taken out that the operator " ∆ " first subtracts the two numbers and then squares the obtained value to get the result . That is ,

\sf\implies m \Delta n = ( m - n )^2

Now similarly let's simplify out 3 ∆ 2.

Step 1 : <u> </u><u>Subtra</u><u>ct</u><u> </u><u>the </u><u>two</u><u> </u><u>numbers</u><u> </u><u>:</u><u>-</u><u> </u>

This means we need to subtract 2 from 3 . This will give result as ,

\sf\implies Result_1 = 3 - 2 =\pink{1}

Step 2 : <u>Square </u><u>the</u><u> </u><u>obta</u><u>ined</u><u> </u><u>val</u><u>ue</u><u> </u><u>:</u><u>-</u><u> </u>

Here , the value obtained from step 1 is 1 and the square of 1 is 1 . So our final result would be,

\sf\implies Result_{(final)}= 1^2 = \boxed{\pink{ 1 }}

jeka943 years ago
5 0

since m▲n=m^2-2mn+n^3

3▲2=3^2-2*3*2+2^3

=9-12+8

=17-12

=15

Done!

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