We will need to have two equations here, having x as the missing length. We know that the chairs are in the same amount on each occasion, so each equation should be equal to the other.
This sets up a problem of:
6x + 7 = 4x + 13
7 and 13 being the leftover chairs and 6 and 4 being the rows. Let’s solve for x.
x = 3
Knowing this, we plug in x for one of the equations
6(3) + 7
18 + 7
25
Liam has 25 chairs.
Answer:
it stays the same because there is no simplifying it and the re are no like terms
R = ((3V)/((pi)(h^2))+h)/3
