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2 years ago

1.2x-4y=28 solve for y

1 answer:

4 0

2x -4y= 28
⇒ -4y= 28 -2x
⇒ y= (28 -2x)/ (-4)
⇒ y= 28/(-4) -(2x)/ (-4)
⇒ y= -7 + 1/2x

The final answer is y= -7 + 1/2x~

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PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$ AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units

8 0

2 years ago

Simplify 6 - (-2) - 3(-5)

seraphim [82]

So the first thing we need to do is multiply 3*-5, since order of operations dictates it (PEMDAS)

$6-(-2)-(-15)$

Now, whenever we see a minus negative number, we can think of it as adding a positive number

$6+(+2)+(+15)$

Now we just add them together

$6+2+15 = 23$

23 is the answer

8 0

3 years ago

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In a village the number of houses and the number of flats are in the ration9:5 the number of flats and the number pf bungalows a

Dmitry_Shevchenko [17]

Answer: 180 houses

Step-by-step explanation:

From the question, we are informed that in a village the number of houses and the number of flats are in the ratio 9:5 while the number of flats and the number of bungalows are in the ratio 10:3 and that there are 30 bungalows in the village.

Since the ratio of the number of flats and the number of bungalows are in the ratio 10:3 and there are 30 bungalows in the village, the number of flats will be:

= 10/3 × 30

= 10 × 10

= 100 flats

Since we are told that the ratio of the number of houses to the number of flats are in the ratio 9:5 and we've gotten the number of flats as 100, then the number of houses will be:

= 9/5 × 100

= 9 × 20

= 180 houses

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2 years ago

5000/210= with the remainder as a fraction

Softa [21]

The answer is 23 4/5

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