Answer:
± 
, 
Step-by-step explanation:
See the attached image
This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are:
that correspond to the force of resistance on the mass by the action of the spring and
that is an external force with unknown direction (that does not specify in the enounce).
For determinate
we can use Hooke's Law given by the formula
where
correspond to the elastic constant of the spring and
correspond to the relative displacement of the mass-spring system with respect of his rest state.
We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

Now we apply Newton's 2nd Law and obtaint that...
±
= 




Finally...
± 
We know from the problem that there's not initial displacement and initial velocity, so...
and 
Finally the Initial Value Problem that models the situation describe by the problem is

Answer:
(0.5, 1.3)(0.5, 1.3)
Step-by-step explanation:
Given equations are:
As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.
We can plot the graph of both equations using any online or desktop graphing tool.
We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)
We can see from the graph that the lines intersect at: (0.517, 1.267)
Rounding off both coordinates of point of intersection to nearest tenth we get
(0.5, 1.3)
Hence,
(0.5, 1.3) is the correct answer
Keywords: Linear equations, variables
Answer:
v=2
Step-by-step explanation:
30mi/2hr
Explanation: just divide both by two. It won’t always work like this. You can’t always divide something by 2 to get 2. Find a number that will go into the denominator two times and divide the numerator by it also.