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bagirrra123 [75]
3 years ago
14

Which of the following is an asymptote of y = sec(x)?

Mathematics
2 answers:
babunello [35]3 years ago
8 0
Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

Answer: 3π/2

The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).

shutvik [7]3 years ago
5 0

Answer: The answer is D


Step-by-step explanation:


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